If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2+53x-18=0
a = 3; b = 53; c = -18;
Δ = b2-4ac
Δ = 532-4·3·(-18)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-55}{2*3}=\frac{-108}{6} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+55}{2*3}=\frac{2}{6} =1/3 $
| 3a-a-4=-2 | | 8a-2a+3=9 | | 8+9a=71-9 | | 2^(x-5)=3 | | 5x−7(-x+2)=58 | | 4a+9=6a-5 | | -2a-13=-3a-5 | | Y^4-2y^2=4 | | 4/x+1/(2x)=9/4 | | 2a-3a+12=a+2 | | X+(x+1)+(x+3)=64 | | 0.6x=0.1x+7 | | 4/x+1/2x=9/4 | | x-2.25=83/4 | | 24(t)=16t^2+24t+4 | | (x-4)(7-x)=5-x2 | | 2-2x=-5-4 | | x/3=154 | | 4+3+4x15=x | | -16*t^2+18*t=0 | | 2+2x-3=6-x-1 | | 3x+1-5x=-11+x | | 5t^2-11t+3=0 | | 2x-2-4x=-4 | | 3x-5+4x=7-2x-3 | | 2x-3+2x=7-x | | 5a^2-18=-6a | | 4x^2=2(x+1) | | 9x=378 | | 7.5x-8.2=14.3 | | 9x-14=17-3x | | 7.7x-15.5=-0.1 |